Homework Answers
Sickle cell anemia is an autosomal recessive trait.
Genotype of affected individual = Sc-Sc-
Genotype of normal individual = Sc+Sc+, Sc+Sc- (carrier)
According to the question,
Genotype of both parents = Sc+Sc- (carrier)
Parents = Sc+Sc- × Sc+Sc- = F1 generation
| Gametes | Sc+ | Sc- |
| Sc+ | Sc+Sc+ (normal) | Sc+Sc+ (carrier) |
| Sc- | Sc+Sc- (carrier) | Sc-Sc- (affected) |
Total number of progeny = 4
Normal progeny = 1/4
Carrier progeny = 2/4
Affected carrier = 1/4
Mr Candy is a carrier and according to punnet square, the probability of Mr Candy or any other progeny being carrier is 50%, and to be affected is 25%.
Genotype of Mr Candy = Sc+Sc-
Genotype of wife = Sc+Sc+
Progenies of Mr Candy and his wife
| Gametes | Sc+ |
| Sc+ | Sc+Sc+ (normal) |
| Sc- | Sc+Sc- (carrier) |
Number of progeny = 2
Normal progeny = 1 = 50%
Carrier progeny = 1 = 50%
There is an equal chance of progeny being normal and a carrier.
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