6)
As it is well known that saturated fatty acids esters (triacylglycerol) are well ordered and have stronger dispersion forces between their chains. These fatty acids have higher melting point and melts above room temperature while unsaturated fatty acid esters (triacylglycerol) are less ordered and the dispersion forces between unsaturated chains are weak. Therefore, these esters have low melting point. On increasing the number of double bonds, the melting point of fatty esters decreases.
Triacylglycerol A: This compound contains three saturated long chain fatty acids. (well-ordered and stronger dispersion forces)
Triacylglycerol B: This compound contains two saturated and one unsaturated (one double bond) long chain fatty acids (ordered and weaker dispersion forces than A).
Triacylglycerol C: This compound contains one saturated and two unsaturated (two double bond) long chain fatty acids (less ordered and weaker dispersion forces than B).
Triacylglycerol D: This compound contains three unsaturated (two double bond each = six double bond) long chain fatty acids (less ordered and weakest dispersion forces).
Triacylglycerol E: This compound contains three saturated and longer chain fatty acids than compound A. (well-ordered and stronger dispersion forces than compound A)
Thus, based on these concept, the order of melting point of these triacylglycerols is as
E > A > B > C > D
number 6 5.) (5 pts) Draw the structure of the following triacylglycerols: (A) 1-Lauroyl-2-palmitoyl-3-myristoyl g...
1. Name the following or Draw the Structure (2 x 3 pts each) a. N-methyl-3-phenylpentan-2-amine OH b. OH NH2O 2. Draw the starting materials for the following hydrolysis reactions. (3 pts each) 1. NaOH, H2O a. 3-or 2. HCI, H2O OH OH Ph 1. NaOH, H2O b. HO Н. CH3 OH HPh 2. HCI, H2O 3. Of the following, which form would actually exist at: (5 points) a) pH = 2 (acidic) b) pH = 7 (neutral) c) pH =...