a. A student dissolved 20.00 g of Na2SO4 in enough water to make 250 mL of stock solution. How many mL of the stock solu...
a. A student dissolved 20.00 g of Na2SO4 in enough water to make 250 mL of stock solution. How many mL of the stock solution would the student need to use in order to make a 150 mL of 0.100 M solution?
b. In an acid-base titration, 82.56 mL of 0.175 M NaOH titrant reacts with 100.0 mL of an unknown concentration of HCl solution. What is the density of the HCl solution?
Homework Answers
ANSWER:-
A)- GIVEN WEIGHT=20.0gm of Na2SO4 and volume is 250 ml molar mass of Na2SO4 is 142g
so first you have to calculate the molarity of Na2SO4 solution from the formula
molarity M = w * 1000/m * v
M= 20g * 1000(ml)/142g * 250 ml
M1= 0.56 of (Na2SO4) then use formula
M1V1 = M2V2
0.56 * V1 = 150 * 0.100
V1= 26.78 mL
SO, 26.78 ml of stock solution will use.
B)- FOR CALCULATE THE DENSITY WE SHOULD FIRST CALCULATE THE MOLARITY OF HCL SOLUTION USING FORMULA,
M1V1 = M2V2
82.56 ml (NaOH) * 0.175M = 100 ml(HCL) * M2
MOLARITY OF HCL =0.144 M
then we use molarity formula for calculating density
molarity = w * 1000/m * v
and we know that density = m/v
so from above formula
molarity = d *1000/m
and density = molarity * m/1000
where m(molar mass) of HCL = 36.45
so density d= 0.144M * 36.5(g)/ 1000(ml)
(density of HCL) d= 0.005256 g/ml
ANSWER:-
A)- GIVEN WEIGHT=20.0gm of Na2SO4 and volume is 250 ml molar mass of Na2SO4 is 142g
so first you have to calculate the molarity of Na2SO4 solution from the formula
molarity M = w * 1000/m * v
M= 20g * 1000(ml)/142g * 250 ml
M1= 0.56 of (Na2SO4) then use formula
M1V1 = M2V2
0.56 * V1 = 150 * 0.100
V1= 26.78 mL
SO, 26.78 ml of stock solution will use.
B)- FOR CALCULATE THE DENSITY WE SHOULD FIRST CALCULATE THE MOLARITY OF HCL SOLUTION USING FORMULA,
M1V1 = M2V2
82.56 ml (NaOH) * 0.175M = 100 ml(HCL) * M2
MOLARITY OF HCL =0.144 M
then we use molarity formula for calculating density
molarity = w * 1000/m * v
and we know that density = m/v
so from above formula
molarity = d *1000/m
and density = molarity * m/1000
where m(molar mass) of HCL = 36.45
so density d= 0.144M * 36.5(g)/ 1000(ml)
(density of HCL) d= 0.005256 g/ml
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