Question

Have I done part f) and g) correctly?

PART A: Structures Questions Three (3) questions; Answer all questions; The questions carry the number of marks indicated; Total marks for Part A is 24. Answer the questions on this Examination Question Paper in the spaces provided. Nothing written on an answer booklet, on scrap paper or else where will be marked for Part A. Signs and units are an essential part of any answer. Some formulas and solutions of elastic curves of beams in bending provided on the last two pages of the examination papeer. are Question A1 (9 marks) A two meter long composite timber I-beam AB (Young's modulus E 10 GPa, second moment of area I 2.06 105 mm4) is manufactured from three parts which are nailed together as shown. It is simply supported and loaded by a force P 2 kN. y P s-90 mm 0.6 m 1.4 m 5 mm 10 mm- A 40 mm N -30 mm- S mm a) Draw the free body diagram of the beam, and give the values of the reactions you have introduced at the supports A and B. (1 mark) EMAZO=INXIOx0-6+2XB B-6 00M Fy 2000t600t4 TB Ag A=1400N b) Sketch the shear force and bending moment diagram and determine the magnitude and location of the maximum shear force and bending moment. (1 mark) Bending moment diagram Shear force diagram Maximum bending moment Magnitude: Maximum shear force Magnitude: Location(s): 6M Location(s): A truciures and Materials Semester One Final Examinations, 2016 (2 marks) c) Determine the maximum normal stress in the beam. Mb Cmay d) Make a qualitative sketch of the shear stress distribution tlv) that exists in any cross section along the beam. (1 mark) e) What is the fundamental equation that is used to calculate the shear stress distribution ty(y)? Use the second box to describe the physical quantities that the variables in the equation represent either in words and/ or using a sketch. (2 marks) VIfotce -Istmom. gred エー2nd ノ Ft / tー ナんckness f) Determine the minimum shear stress capacity Deg of the timber, (1 mark) Treg g) Determine the minimum shear force capacity Freg of the nails. (1 mark) 30 75 Freg zo0x30X5 20) X12 5 282916イ7X10xノd - 3.09p Ve 20 zo00x30x5+10×20)×/25メ90 282916.7 ミ 27835N 全 F =1= Page 3 of 17

Answer 1

(9) Ayao 1,4m Ar- MA O niven 2kXo-6 +g 2 0 1.2 600 Ihan Ay2k-89 NGO11 = QPht 9 = B for ca dlagram (by Shear 084kent -6K 86kN ko.bm-te .4m makimum bend ing momat magnitude 0.24k n Locahion- Ato 0.6m Maximum Shear for mugnituele- 1.41k Point (A) print fis tane A. maximum nirmal stess M c I 1o mn m 1 3mm I Z(I +A2) + (0.03) (0.01 0.0215) = 2 +

Ceusm) (24511-m max 1.8434x1 184,3NP 2 hoare 2-Shogr shress intonal resulten Shes momaut ofin arhie I mebey ls cmrass Sehonad widtn t ared A' Arentop prstin f the menber Crso ss Sochonal asry JB teince frm the nouhr a mari Shaarr ats o.125x (0.00o Is) ( 1400 Anu2 It 2O5X101 G.01 1.28 X1.N,m 1.28 NPO

x (30x5+1ox2s) X12- 28 291616 XI min It 3.07 2000 x(30xs + teX) X 12 S I 282916. 2783SN