Question

1. Find the loss in stagnation pressure through a normal shock with an incoming flow at a Mach number of 2 and incoming flow stagnation pressure of 200 kPa(abs). In addition to the stagnation pressure downstream of the shock, also give the Mach number and (static) pressure downstream of the shock. DISCUSSION: Compare the "shock compression" (increase in STATIC pressure) obtained from the normal shock to the compression that would be obtained from an isentropic deceleration to the same Mach number as that obtained downstream of the normal shock

Answer 1

upskcam of thu shock , mach number m, = 2 given tha Stagnaltm pre surc Po, 200 kfa From Tenophit tablu at mach number m,c 2 the ratio P Po stati precur upskcarn of the shock P = 0'1216 x Po O'12ex aoo Doonsream Frem NoTmal shock tablet at mach number m,- i upsheum daunsham mach number the Por stauc pvessurc ralio the 4'5xP shocle 4.5x 25 56 B stalic pressu d awnshcam of the sheack PI5b2ŁPa stagnation pressurt ratb PoI Po2 the 0109 x Po Por Po = o20 x 200 Po 4-18 kPa shock daon stea mf the stagnation pressue at the the NOISSaSIa Increage in shalic Prcssu PL-PI due to normal shock is - the IS o2-2S'56 sentmphic decceloraton , Stagnahn precsue Aemalns Constant PoPor At mL 5 from semtaphic tables ES Scanned Pvith p a962 CamScaer

Fo1962.X 20D o1962 x Po2 PL P /59.24 kPa P-P n statc pre ssur chang The 59 24- 25 S6 33 6 Pa Tsentrophic decele ration as Same mach number at the donstream, Compared stalic prcssuwe is more 9Incrcase n in with the normal shock for the cS Scanned with CamScanner