Modify the circuit to support a MFCC instruction.
MFCC Rd instruction: Move From Condition Codes
MFCC copies into the four rightmost bits of Rd the values of the
ALU signals Carry (C), Overflow (O), Zero (Z) and Negative (N) as
they were set by the previous R- type instruction. The remaining 28
bits of Rd are set to zero.
Describe the changes and additions needed for the single-cycle MIPS processor datapath and control to support this instruction.
Hints:
1) MFCC is an I-type instruction.
2) The control unit produces a signal called RType which is set to
1 if the decoded instruction is any R-type instruction and 0
otherwise.
3) The control unit produces a signal called MFCC which is set to 1
if the decoded instruction is MFCC and 0 otherwise.
4) The four signals Carry (C), Overflow (O), Zero (Z) and Negative
(N), come from the ALU. N indicates if the value coming out of the
ALU is negative.
5) Since MFCC gets the information from the previous R-type
instruction, this means that the ALU signals must be latched in
flip-flops by R-type instructions so they can be used by MFCC.
Homework Answers
Add Answer to:
Modify the circuit to support a MFCC instruction. MFCC Rd instruction: Move From Condition Codes MFCC copies into the fo...
*For a clearer view of the datapath* Answer choices for all Consider the MIPS single cycle...
*For a clearer view of the datapath*
Answer choices for all
Consider the MIPS single cycle datapath shown below. Select the correct control signals that will be generated by the control unit for the following instruction: andi $t0,$t1,4 Instruction (25-01 Shin Jump address (31-0) - left 2) 28 PC +4 [31-28) XCS result left 2 RegDst Jump Branch MemRead Instruction (31-26] MemtoReg Control ALUOP MemWrite ALUSrc RegWrite Instruction (25-21] PC Read address Read register 1 Read Instruction (20-16] Read data...
Assume that ‘slt $1, $2, $3’ is executed with the implementation in the picture. Identify the value of the 9-bit control...
Assume that ‘slt $1, $2, $3’ is executed with the implementation
in the picture. Identify the value of the 9-bit control
signals.
Add u X ALU result 4 Add Shift left 2 RegDst Branch MemRead MemtoReg Control ALUOP Instruction [31-26 MemWrite ALUSRC RegWrite Instruction [25-21] Read register 1 Read Read PC address Instruction [20-16] data 1 Read Zero register 2 Instruction ALU ALU 31-0] Instruction memory Read data M Read Address Write result u M Instruction [15-11] register data 2...
Add 9 MUX 4 4 Addresult ALU Shift left 2 RegDst Branch MemRead Instruction (31-26) Control...
Add 9 MUX 4 4 Addresult ALU Shift left 2 RegDst Branch MemRead Instruction (31-26) Control Memto Reg ALUOD MemWrite ALUSC RegWrite Instruction [25-21) Read PC Read address register 1 Read Instruction (20-16] MUX1 MUX Zero ALU ALU MUX3 M Instruction (31-0) Instruction memory Road Address data Read data 1 register 2 Write Read register data 2 Write data Registers result Instruction (15-11] Fox SX) Data Write data memory 16 32 Instruction (150) Sign- extend ALU control Instruction (5-0)
(o x Add Addresult ALU Shift left 2 Regst Branch MemRead Instruction (31-26) MemtoReg Controll ALUOP...
(o x Add Addresult ALU Shift left 2 Regst Branch MemRead Instruction (31-26) MemtoReg Controll ALUOP MemWrite ALUSC RogWrite Instruction [25-21] Read register 1 Read Instruction (20-16) Read data 1 register 2 Write Read Instruction (15-11) Write data Registers PC Read address Zoro ALU ALU Instruction (31-0) Instruction memory result Address Read data register data 2 **039 -25 Write Data data memory Instruction (15-01 16 Sign- extend ALU control Instruction 15-01 With regards to the single cycle implementation (as shown...
MCS) Add Addresult ALU Shift left 2 RegDst Branch MemRead MemtoReg Instruction (31-26] Control ALUOP MemWrite...
MCS) Add Addresult ALU Shift left 2 RegDst Branch MemRead MemtoReg Instruction (31-26] Control ALUOP MemWrite ALUS RegWrite PC instruction (25-21] Instruction (20-16) Read address Instruction (31-0) Instruction memory Read register 1 Read Read data 1 register 2 Write Read Zoro ALU ALU result Address Read data instruction (15-11] register data 2 x3) Write data Registers Write Data data memory Instruction 15-01 16 Sign- extend ALU control Instruction (5-0) With regards to the single cycle implementation (as shown in the...
Q4: Answer the following questions. [7 Marks] The single cycle implementation of MIPS is as shown...
Q4: Answer the following questions. [7 Marks] The single cycle implementation of MIPS is as shown below. Answer the following questions with reference to "beq $S1, $S2, 8H” instruction. Assume that the contents of the registers S1 = 10 H, S2 = 10H, and PC = 16H, pointing to the instruction under consideration. 1. What is the addressing mode of the instruction? [1] ii. Which part of the instruction format, address of S1 and S2 are stored? [1] 111. What...
6. Consider a datapath similar to the one in figure below, but for a processor that only has one type of instruction: unconditional PC-relative branch. What would the cycle time be for this dat...
6. Consider a datapath similar to the one in figure below, but for a processor that only has one type of instruction: unconditional PC-relative branch. What would the cycle time be for this datapath? PCSrc Add ALU Add result Shift +( left 2 Read register 1 ALUSrc, 4 ALU operation PCRead PC-address Read data 1 Registers Read data 2 MemWrite Zero ALU ALU-I Address MemtoReg Instruction register 2 Instruction | Write Read data-M register Write Lu memory Write Data data...
Question 5 0.25 pts What is the value of the MemWrite control signal? Question 6 0.25 pts What is the value of the ALUSrc control signal? Add Add Sum--(1 4 Shift left 1 Branch MemRead Instruction [6-...
Question 5 0.25 pts What is the value of the MemWrite control signal? Question 6 0.25 pts What is the value of the ALUSrc control signal? Add Add Sum--(1 4 Shift left 1 Branch MemRead Instruction [6-0] ControMemtoReg MemWrite ALUSrc RegWrite Instruction [19-15]Read Read register 1 Read Read data! PCaddress Instruction [24-20] Zero ALU ALU result register 2 Instruction 31-0 Instruction [11-7 Read1 Address data | Write Read register daiaALU | M Instruction memory Write data Registers Write Data data...
it is the same question A block diagram of MIPS architecture is given below. What is...
it is the same question
A block diagram of MIPS architecture is given below. What is the value of the control bit for each MUX during the execution of the given instruction? Note, you may use N/Aif MUX output is not usefu Add MUX 4 ALU Add, result Shift left 2 RegDst Branch MemRead Instruction (31-26] Control Memto Reg ALUOP Mem Write ALUSrc RegWrite Instruction [25-21) PC Read address Instruction (20-16] MUXT Read register 1 Read Read data 1 register...
A block diagram of MIPS architecture is given below. What is the value of the control...
A block diagram of MIPS architecture is given below. What is the
value of the control bit for each MUX during the execution of the
given instruction? Note, you may use N/A if MUX output is not
useful.
Add MUX 4 ALU Addresult Shift left 2 RegDst Branch MemRead Instruction (31-26] MemtoReg Control ALUOp MemWrite ALUSrc RegWrite Instruction [25-21] PC Read address Read register 1 Read Read data 1 register 2 Write Read MUX 2 Zero Instruction (2016) MUX(1 Instruction...
*For a clearer view of the datapath*
Answer choices for all
Consider the MIPS single cycle datapath shown below. Select the correct control signals that will be generated by the control unit for the following instruction: andi $t0,$t1,4 Instruction (25-01 Shin Jump address (31-0) - left 2) 28 PC +4 [31-28) XCS result left 2 RegDst Jump Branch MemRead Instruction (31-26] MemtoReg Control ALUOP MemWrite ALUSrc RegWrite Instruction (25-21] PC Read address Read register 1 Read Instruction (20-16] Read data...
Assume that ‘slt $1, $2, $3’ is executed with the implementation
in the picture. Identify the value of the 9-bit control
signals.
Add u X ALU result 4 Add Shift left 2 RegDst Branch MemRead MemtoReg Control ALUOP Instruction [31-26 MemWrite ALUSRC RegWrite Instruction [25-21] Read register 1 Read Read PC address Instruction [20-16] data 1 Read Zero register 2 Instruction ALU ALU 31-0] Instruction memory Read data M Read Address Write result u M Instruction [15-11] register data 2...
Add 9 MUX 4 4 Addresult ALU Shift left 2 RegDst Branch MemRead Instruction (31-26) Control Memto Reg ALUOD MemWrite ALUSC RegWrite Instruction [25-21) Read PC Read address register 1 Read Instruction (20-16] MUX1 MUX Zero ALU ALU MUX3 M Instruction (31-0) Instruction memory Road Address data Read data 1 register 2 Write Read register data 2 Write data Registers result Instruction (15-11] Fox SX) Data Write data memory 16 32 Instruction (150) Sign- extend ALU control Instruction (5-0)
(o x Add Addresult ALU Shift left 2 Regst Branch MemRead Instruction (31-26) MemtoReg Controll ALUOP MemWrite ALUSC RogWrite Instruction [25-21] Read register 1 Read Instruction (20-16) Read data 1 register 2 Write Read Instruction (15-11) Write data Registers PC Read address Zoro ALU ALU Instruction (31-0) Instruction memory result Address Read data register data 2 **039 -25 Write Data data memory Instruction (15-01 16 Sign- extend ALU control Instruction 15-01 With regards to the single cycle implementation (as shown...
MCS) Add Addresult ALU Shift left 2 RegDst Branch MemRead MemtoReg Instruction (31-26] Control ALUOP MemWrite ALUS RegWrite PC instruction (25-21] Instruction (20-16) Read address Instruction (31-0) Instruction memory Read register 1 Read Read data 1 register 2 Write Read Zoro ALU ALU result Address Read data instruction (15-11] register data 2 x3) Write data Registers Write Data data memory Instruction 15-01 16 Sign- extend ALU control Instruction (5-0) With regards to the single cycle implementation (as shown in the...
Q4: Answer the following questions. [7 Marks] The single cycle implementation of MIPS is as shown below. Answer the following questions with reference to "beq $S1, $S2, 8H” instruction. Assume that the contents of the registers S1 = 10 H, S2 = 10H, and PC = 16H, pointing to the instruction under consideration. 1. What is the addressing mode of the instruction? [1] ii. Which part of the instruction format, address of S1 and S2 are stored? [1] 111. What...
6. Consider a datapath similar to the one in figure below, but for a processor that only has one type of instruction: unconditional PC-relative branch. What would the cycle time be for this datapath? PCSrc Add ALU Add result Shift +( left 2 Read register 1 ALUSrc, 4 ALU operation PCRead PC-address Read data 1 Registers Read data 2 MemWrite Zero ALU ALU-I Address MemtoReg Instruction register 2 Instruction | Write Read data-M register Write Lu memory Write Data data...
Question 5 0.25 pts What is the value of the MemWrite control signal? Question 6 0.25 pts What is the value of the ALUSrc control signal? Add Add Sum--(1 4 Shift left 1 Branch MemRead Instruction [6-0] ControMemtoReg MemWrite ALUSrc RegWrite Instruction [19-15]Read Read register 1 Read Read data! PCaddress Instruction [24-20] Zero ALU ALU result register 2 Instruction 31-0 Instruction [11-7 Read1 Address data | Write Read register daiaALU | M Instruction memory Write data Registers Write Data data...
it is the same question
A block diagram of MIPS architecture is given below. What is the value of the control bit for each MUX during the execution of the given instruction? Note, you may use N/Aif MUX output is not usefu Add MUX 4 ALU Add, result Shift left 2 RegDst Branch MemRead Instruction (31-26] Control Memto Reg ALUOP Mem Write ALUSrc RegWrite Instruction [25-21) PC Read address Instruction (20-16] MUXT Read register 1 Read Read data 1 register...
A block diagram of MIPS architecture is given below. What is the
value of the control bit for each MUX during the execution of the
given instruction? Note, you may use N/A if MUX output is not
useful.
Add MUX 4 ALU Addresult Shift left 2 RegDst Branch MemRead Instruction (31-26] MemtoReg Control ALUOp MemWrite ALUSrc RegWrite Instruction [25-21] PC Read address Read register 1 Read Read data 1 register 2 Write Read MUX 2 Zero Instruction (2016) MUX(1 Instruction...
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