Homework Answers
no of moles of KHP = W/G.M.Wt
= 0.503/204.22
= 0.00246mole
KHP(aq) + NaOH(aq)----------> KNaP(aq) + H2O(l)
1 mole of KHP react with 1 mole of NaOH
0.00246moles of KHP react with 0.00246moles of NaOH
no of moles of NaOH = molarity *volume in L
0.00246 = molarity*0.0273
molarity = 0.00246/0.0273 = 0.09M
molarity of NaOH = 0.09M
a. 0.09M >>>answer
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please help me speciqlly with 11. 12. 13. 14 Experiment 7, Analysis of KHP by titration...
please help me speciqlly with 11. 12. 13.
14
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please help me speciqlly with 11. 12. 13.
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please write out calculations for each box missing an answer
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