Question

84. Hydrogen can be extracted from natural gas according to the reaction: CH4(8) + CO2(g) = 2 CO(g) + 2 H2(g) Ky = 4.5 x 102 at 825 K An 85.0-L reaction container initially contains 22.3 kg of CH4 and 55.4 kg of CO2 at 825 K. Assuming ideal gas behavior, calcu- late the mass of H, (in g) present in the reaction mixture at equi- librium. What is the percent yield of the reaction under these conditions? CaO(s) : 90. An equi (P = 1. at cons the rea gases w 91. Carbon СО

Answer 1

Solution : Given that : a Chu 9 tCO2 ) = acog) + 2H₂ 9 Kp = 4.54102 at 825 kr Mole of CH4 = 22.3 kg xi mor - 1390]mol 16.043 X10-3 kg Imol Moles of con 5504&g x 4400091103 to 11260/mol = 4.5*102 0.0831 x 825 ) 2 . 4.5x102 - 450 55,879.3125 67.7325 = 0.0982.) CH4 t co2 Initial emol). 1390 Change (Mol - Fulibrium (mol) 1390-2 Frülibrium (mods 1390-X asio = aco & QH₂. 1260 0 nde . fox 12600 22 i teix 1260- : 8500 2x 35.0 8500 25.0 85.0 85.0

ke = [co] [Hz]² Cetty] [cor Sometimes besteht .de 2 0.0982 - 85.0 85.0 60- - 1390-2 850 - 0.0982 = 2.21 x x xH (1390–2) (1260-2) 0.0980 - 2021 x103 xxy . (1990 m2) (1260-"). = * = 190.65 )amo) Mass of He at eruilibrium =2x90.65 mol - 2x90.65 Hz x 2.016.S - 2 x 40.65 H 2.0169 =(266.Ja Hz 1 mol H2

B cg is the limiting reaction : .. 2nd H₂ 1260 mot co2x Into . x 2016 g mol H2 = 5080.3 g/ percent yield = Noo Actual therotical = 366 Χίοο 50803 -70%) 72A