You dissolve some solid Na2C2O4 in water to make 100.0 mL of 0.1M solution. You add...

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You dissolve some solid Na2C2O4 in water to make 100.0 mL of 0.1M solution. You add...

You dissolve some solid Na2C2O4 in water to make 100.0 mL of 0.1M solution.

You add 50.0 mL of 0.20M HCL. What is the pH of the resulting solution?

What is the pH after 75.0mL of HCl (total) is added?

pka1 = 1.25, pka2 = 4.27

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Answer 1

Answer #1

1)

millimoles of Na2C2O4 = 100 x 0.1 = 10

millimoles of HCl = 50 x 0.2 = 10

C2O42- + H+ --------------------> HC2O4-

10 10 0

0 0 10

HC2O4- is the intermediate salt . its pH depends on pKa and pKa2 but not concentration

pH = 1/2 [pKa1 + pKa2 ]

pH = 1/2 [1.25 + 4.27 ]

pH = 2.76

2)

millimoles of HCl = 75 x 0.2 = 15

C2O42- + H+ --------------------> HC2O4-

10 15 0

0 5 10

HC2O4- + H+ --------------------> H2CO3

10 5 0

5 0 5

pH = pKa1 + log (HC2O4- / H2CO3)

pH = 1.25 + log (5/5)

pH = 1.25

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Answer 2

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