Question

1. A wooden rod of length 40.0 cm and mass 1.00 kg is sitting on a frictionless horizontal surface. The rod has a pin through its centre so that it can freely rotate about a vertical axis perpendicular to the rod and passing through the center of the rod. A projectile of mass 0.0100 kg is now shot at the rod. The projectile is moving horizontally with a speed of 2.00 x 102 m/s in the direction perpendicular to the rod at the instant that it strikes one end of the rod. The projectile embeds in the rod. You may assume that the projectile embeds in the rod before the rod/projectile system starts to rotate. axis rod projectile (a) Just prior to the collision of the projectile with the rod, calculate the angular momentum of the projectile with respect to the vertical axis through the centre of the rod. (b) Calculate the moment of inertia of the rod/embedded projectile system with respect to the vertical axis through the centre of the rod. (c) Calculate the angular speed of the rod with embedded projectile.

Answer 1

a) b) Angular momentum is. La muer - 0.010( 2x10?) (0-yom) - 0.4 kg. in sec. I = mL mer - 160.40) 10011(0.200 12 = 0.01373 kg. nr 1 Angular speed w - Tangular momentum = 0.4 0.01373 - 29.126 reader