Is P(x) V(x) equivalent to x(P(x) V Q(x))? Explain Is P(x) V(x) equivalent to x(P(x) V...
Select the logical expression that is equivalent to: 3x(P(2) AQ(x)) ( P(x) V-Q(x)) Vo(-P(x)^-Q(x)) V«(- P() V-Q()) O 3:(-P(x)^-Q(:))
Select the logical expression that is equivalent to: -Vx3y(P(2) A Q(x,y)) Vydt-P(1) V-Q(x,y)) yV:( P(1) VQ(x,y)) 3rVy(P(x) V-Q(,y)) VxJy(P(x) VQ(x,y))
Show that ~p -> (q -> r) and q-> (p v r) are logically equivalent
QUESTION 23 The statements P + (Q v R) and (P +Q) v (P + R) are logically equivalent. True False QUESTION 24 The statements (P^Q) + Rand (P + R)^(Q + R) are logically equivalent. True False QUESTION 25 ( PQ) and PA-Q are logically equivalent statements True False QUESTION 26 According to De Morgan's Laws, (PAQ) is logically equivalent to 7P ^ 70. True False
2. (a) Show that (PVQ) + R is not logically equivalent to (P + R) V(Q + R) using a truth table. (b) Is (PAQ) → R logically equivalent to (P + R) A( Q R )? If so, use a truth table to establish this. If not, show that it is false.
¬ ∀x ( P(x) -> Q(x)) = ∃ x (¬ P(x) V Q(x)) True False (i > =1) → (j < 5) = (i< 1) V(j <5) True False ¬((i > 2) Λ(j <= 3)) = (i<= 2) V(j <3) True False
6. Maximum score 3 ( 1 per part).Show that:(b) (p → q) → r and p →(q → r) are not logically equivalent.(c) p ↔ q and ¬ p ↔ ¬ q are logically equivalent.
Determine the domain of each of the functions P(x), Q(x), V(x), and Z(x). Select the one row that gives the correct domain underneath each function. P(x)= x2 + 1 Q(x) = Ne + 1 V(r) = **1 Z(x) = log (x + 1) OP: [-1, )Q: (-00, -1) (-1,00) V:(-0,0) Z: (-1,00) OP: (-00,00) Q: (-1,0) V: (-00, -1) (-1,0) Z: (-1,00) OP: (-00,00) Q: (-1,-) V: (-0, -1) U (-1,00) Z: (-1,0) OP: (-0, -1) U (-1,0) Q: (-1,-)...
Assume that p NAND q is logically equivalent to ¬(p ∧ q). Then, (a) prove that {NAND} is functionally complete, i.e., any propositional formula is equivalent to one whose only connective is NAND. Now, (b) prove that any propositional formula is equivalent to one whose only connectives are XOR and AND, along with the constant TRUE. Prove these using a series of logical equivalences.
How do you show the following propositions are logically equivalent? (a) [(p → q) → r] ⊕ (p ∧ q ∧ r) and (p ∨ r) ⊕ (p ∧ q) (b) ¬∃x {P(x) → ∃y [Q(x, y) ⊕ R(x, y)] } and (∀x P(x)) ∧ [∀x ∀y(Q(x, y) ↔ R(x, y))] (c) Does [(p → q) ∧ (q → r)] → r implies (p → r) → r?