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The single-line diagram of a three-phase live-bus

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Consider the given circuit diagranm 20.8830 2 -0.2076 3 SD-0.2+jo.1 Vs 5 SD-1.7137+j0.5983 So-1.7355+j0.5496 Qg5 -02 Calculate the admittance at first bus, Substitute the values in above equation, Y?? = 0.0099 + jo0990 + 0.00994 j0.0990 0.0198+ j0.198Similarly, 2 12 Yi,--у,--(0.0099 + J00990) 14- 14 13 Calculate the admittance at second bus, Substitute the values in above eY24-Th =-(0.0099 + jo·0990) 25 Calculate the admittance at third bus, Substitute the values in above equation, Y 0.00990.0990Calculate the admittance at fourth bus, Substitute the values in above equation Y44 = 0.00994 jo.0990 + 0.00994 jo .0990 + 0.Bus 1: Slack bus Bus 2 and 3: PV bus Bus 4 and 5: PQ bus

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The single-line diagram of a three-phase live-bus power system is shown in Fig. 1. All lines...
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