Question

from 298k 1298k Convert given values to 2736 k = 4.3x107 - ke = 4.3x10 m AHA= 1,83 kcal mor gek AHA = 3.55 kcal mol-') ka = 1.7x105 m] 298k DHA = 0.89 kear mei-1] 298k kw= 1x10-14 M] 298k (DHy = 13.35 kcal mar-1] 2981

Answer 1

i) K_a(273) K = 1.7*10^-5 M * e^{(0.89 kcal.mol^-1/0.001987 kcalmol^-1K^-1}.(1/298 - 1/273)K^-1} = 1.48*10^-5 M

ii) K_W(273) K = 1*10^-14 M * e^{(13.35 kcal.mol^-1/0.001987 kcalmol^-1K^-1}.(1/298 - 1/273)K^-1} = 1.27*10^-15 M