Question

The accompanying table shows the numbers of male and lemale students in a certain region who receved bachelor's degrees in a certain fold in a recant year A student is solactod at random. Find the probabiry of esch event ished in parts (a) through (c) below l Cick the icon to viw the table. (a) The studont is male or received a degree in the field The probabäly is (Type an integer or a decimal. Round to three decimal places as needed.) (b) The student is temale or reoeived a degree vlside of the field The probability is Type an intoger or a decimal Round to three decimal places as needed.) (c) The student is not lemale or receired a degree outsido of the takd The protsbility is Table Type an integer or a decimal. Round to free decimal places as needed Degrees Outside of Total 70,988 995,045 1,788,033 Degrees in Field Males Females Total Field 815,381 870,416 155,607 124,629 280.28 1,485,797 1 Print Done

Answer 1

Solution : ( a )

$\mathrm{The\:probability\:of\:the\:student\:is\:male\:or\:received\:a\:degree\:in\:the\:field\:}$

$=\frac{770988+280236-155607}{1766033}$

$=\frac{895617}{1766033}$

$=0.50713\approx 0.507$

$=0.507$

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Solution : ( b )

$\mathrm{The\:probability\:of\:the\:student\:is\:female\:or\:received\:a\:degree\:outside\:of\:the\:field\:}$

$=\frac{995045+1485797-870416}{1766033}$

$=\frac{1610426}{1766033}$

$=0.91189\approx 0.912$

$=0.912$

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Solution : ( c )

$\mathrm{The\:probability\:of\:student\:is\:not\:female\:or\:received\:a\:degree\:outside\:of\:the\:field\:}$

$=\frac{770988+1485797-615381}{1766033}$

$=\frac{1641404}{1766033}\quad$

$=0.92943\approx 0.929$

$=0.929$