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Section 11.7 Exercise 19 Question Help A survey was conducted of the age (in years) of...
Section 11.7 Exercise 20 Question Help A random sample of the amounts for 20 purchases was taken. The mean was $40.23, the standard deviation was $23.31, and the margin of error for a 95% confidence interval was $10.91. Assume that tn-1-2.0 for the 95% confidence intervals. a) To reduce the margin of error to about $5, how large would the sample size have to be? b) How large would the sample size have to be to reduce the margin of...
A survey of 25 randomly selected customers found that their average age was 31.84 years with a standard deviation of 9.84 years. What would the critical value t* be for a 95% confidence interval with 99 degrees of freedom? What would the margin of error be for a 95% confidence interval for this data (with the sample size of 25)? Construct a 95% confidence interval for the mean age of all customers for this data (with the sample size of...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.28 years and the standard deviation is 9.35 31 21 44 32 34 11 48 42 23 45 39 35 31 28 29 43 34 37 20 44 33 27 24 a) Construct a 80% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence interval have been met. b) How large is the margin of...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 33.60 years and the standard deviation is 9.52 years a) Construct a 90% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you had assumed that the standard deviation was known to be 10.0 years?...
In a survey conducted by a reputable marketing agency, 255 of 1000 adults 19 years of age or older confessed to bringing and using their cell phone every trip to the bathroom (confessions included texting and answering phone calls). Complete parts (a) through (f) below. A. Its value may change depending on the individuals in the survey. OB. Its value is based on a specific sample. O C. All pieces of information obtained from surveys are statistics. OD. It is...
In a survey conducted by a reputable marketing agency, 231 of 1000 adults 19 years of age or older confessed to bringing and using the cell phone every trip to the bathroom (contessons included testing and answering phone calls Complete parts (a) tough below Click here to view the standard normal distribution table 1). Click here to view the standard romal distrution lean 21 Why is the pointestinale found in part (c) a random variable? DA being used to make...
years. A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.84 years and the standard deviation is 8.84 25 39 43 25 42p a) Construct a 99% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence 23 28 42 45 31 interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you had assumed...
Section 11.7 Exercise 17-T Ques 14 38 37 34 D A store owner surveyed 25 randomly selected customers and found the ages shown (in years). The mean is 28.72 and the standard devlation is 10.20. The 7 18 22 know if the mean age of all customers is 33 vears old, Use the given information to complete parts a through f. 34 15 22 owner wants 38 28 24 16 32 31 39 38 20 35 15 40 26 42...
A survey was conducted with randomly selected 1012 California residents of age 18 and older. One of the questions on the survey was, “Are you in favor of death penalty for a person convicted of murder?” 693 of the surveyed answered yes. Check the conditions and construct 90% confidence interval for proportion of California residents age 18 or older who are in favor of death penalty. (Find critical value, margin of error, confidence interval, and state the conclusion)
c) Also, would the confidence interval become more narrow, or
more wider?
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.92 years and the standard deviation is 9.73 years a) Construct a 99% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you...