Not sure if any of the filled in answers are correct, so all would be appreciated.
Not sure if any of the filled in answers are correct, so all would be appreciated....
A loan officer compares the interest rates for 48-month fixed-rate auto loans and 48-month variable-rate auto loans. Two independent, random samples of auto loan rates are selected. A sample of eight 48-month fixed−rate auto loans had the following loan rates (all written as percentages): 8.75 7.63 7.26 9.43 7.86 7.20 8.09 8.60 while a sample of five 48−month variable−rate auto loans had loan rates as follows: 7.60 7.00 6.79 7.36 6.99 (a) Set up the null and alternative hypotheses needed...
A loan officer compares the interest rates for 48-month fixed-rate auto loans and 48-month variable-rate auto loans. Two independent, random samples of auto loan rates are selected. A sample of five 48-month variable-rate auto loans had the following loan rates: 2.10% 3.09% 2.873% 3.22% 3.11% while a sample of five 48-month fixed-rate auto loans had loan rates as follows: 4.030% 3.95% 4.390% 3.84% 4.23% Figure 11.7 JMP Output of Testing the Equality of Mean Loan Rates for Variable and Fixed...
A loan officer compares the interest rates for 48-month fixed-rate auto loans and 48-month variable-rate auto loans. Two independent, random samples of auto loan rates are selected. A sample of eight 48-month fixed-rate auto loans and a sample of five variable-rate auto loans had the following loan rates: Fixed(%) Variable(%) 4.29 3.59 3.75 2.75 3.5 2.99 3.99 2.5 3.75 3 3.99 5.4 4 Answer the following questions:( I just need the numbers for the fill in the blanks, no need...
Please help me, I wasn't sure which test to use so I did both of them on excel. Please let me know which is correct and answer A-C. I will give the answer a thumbs up if you can get back to me asap. The physicians also believe that people who are obese are more likely to die earlier than those who are not. Again use the data in the Framingham sample to test this theory by comparing the mean...
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed population of paired differences yields a sample mean d⎯⎯ =4.6d¯ =4.6 of and a sample standard deviation of sd = 7.6. (a) Calculate a 95 percent confidence interval for µd = µ1 – µ2. Can we be 95 percent confident that the difference between µ1 and µ2 is greater than 0? (Round your answers to 2 decimal places.) Confidence interval = [ , ] ;...
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed population of paired differences yields a sample mean d¯ =5.0d¯ =5.0 of and a sample standard deviation of sd = 7.8. (a) Calculate a 95 percent confidence interval for µd = µ1 – µ2. Can we be 95 percent confident that the difference between µ1 and µ2 is greater than 0? (Round your answers to 2 decimal places.) Confidence interval = [ , ] ;...
t-Test: Two-Sample Assuming Equal Variances Variable 1 Variable 2 Mean 12.89795918 17.66666667 Variance 161.2185374 567.8266667 Observations 49 51 Pooled Variance 368.6716646 Hypothesized Mean Difference 0 Df 98 t Stat -1.241549191 P(T<=t) one-tail 0.108683158 t Critical one-tail 1.660551217 P(T<=t) two-tail 0.217366316 t Critical two-tail 1.984467455 Is there a significant difference between the two sample means? If you answer, “yes,” what is your reasoning? If you answer, “no,” what is your reasoning? Please state the conclusion, or your interpretation of the results in terms...
Use the following information to to answer the next question: Mary did an analysis of acute care occupancy rates at two community hospitals and obtained the following results t-Test for Acute Care Occupancy Rates MaxHealth HealthPro Mean Variance Observations Hypothesized Mean df t Stat P(T<t) one-t t Critical one-tail P(T<=t) two t Critical two-tail 62.5461538 108.237692 98.370 ббб67 68.48 Difference 20 1.3923293 0.0895554 1.724718 0.17911147 2.0859 6248 Which of the follow conclusions is correct? (Use α-,05 and the results of...
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed population of paired differences yields a sample mean of d? 5 and a sample standard deviation of sd-7. (a) Calculate a 95 percent confidence interval for μο" μι-P2. (Round your answers to 2 decimal places.) Confidence interval 2.989 7011 (b) Test the null hypothesis Ho: μ.-0 versus the alternative hypothesis Ha: Ha ? 0 by setting ? equal to 10, 05, 01, and .001....
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed population of paired differences yields a sample mean d¯ =4.2 of and a sample standard deviation of sd = 7.6. (a) Calculate a 95 percent confidence interval for µd = µ1 – µ2. Can we be 95 percent confident that the difference between µ1 and µ2 is greater than 0? (Round your answers to 2 decimal places.) Confidence interval = [ ? , ?...