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A sample of an ideal gas goes through the process shown in the figure below. From...

A sample of an ideal gas goes through the process shown in the figure below. From A to B, the process is adiabatic; from B to C, it is isobaric with 345 kJ of energy entering the system by heat; from C to D, the process is isothermal; and from D to A, it is isobaric with 371 kJ of energy leaving the system by heat. Determine the difference in internal energy Eint, BEint, A.
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18.90725 kJ. answer

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E - EA = (5,-E) + (E_ -E») +65-ER C D I so they mal so E -E =0 E - EA - ER-E) + ( E3EA) For process BL 0 = &- EatW 345 = (E-

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