A)The net force on A is:
Fnet = Fab + Fac
Fnet = k q1 (-q2)/0.01^2 + k q1 q2/0.02^2
Fnet = 9 x 10^9 x 0.8 x 10^-9 x 10^-9 (-4.4/0.01^2 + 4.4/0.02^2) = -2.38 x 10^-4 N
Hence, Fnet = -2.38 x 10^-4 N
B)Direction will be :
right
1 of 5 01), Assume that gi=080 nC and 4.4 nC Units up ure right C)...
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