For making stock solution of the antimalarial drug, Artemisinin, how much of Artemisinin (in mg) and...
For making stock solution of the antimalarial drug, Artemisinin, how much of Artemisinin (in mg) and DMSO (in μL) is needed for 35 mM and a total preferred volume of 250 μL? Please show steps.
Note: The max solubility of DMSO is 10 mg/mL and the max concentration of Artemisinin (based off 282.33 g/mol as its molecular weight) is 35 mM.
Homework Answers
Answer:
Molecular weight of Artemisinin= 282.33 g/mol
Required stock= 35 mM= 0.035M
Volume= 250uL= 0.25mL = 0.00025L
Grams= Molarity x ( volume x formula weight)
= 0.035M (0.00025 x 282.33 g/mol)
=0.0024g
=2.4mg
Weight 2.4mg and dissolve it in total of 250uL of DMSO.
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