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C= 1500 \mu F

\varepsilon = 11.5 V

RA = 4000 \Omega

RB = 3000 \Omega

The switch is initially in the right position and the capacitor is completely discharged ( VC = 0 and QC = 0). The switch is moved to the left position and the capacitor starts charging. The switch is kept in the left position for 3.660 seconds, and then the switch is moved to the right position. After being back in the right position for 3.735 seconds, what is the charge on the capacitor?

Charge on C is =

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Answer #1

for charing the capauitsy -tlke 6 sa 3.6 e the Sui yeae 3.73 J 7 875 x 106 b, 436 9 3.4 34 mC Answer

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