What is the moles of NaOH added when the concentration is 500mL and the volume of NaOH added is 10.0mL
Concentration = 500 mM = 500 x 10^-3 M = 0.5 M
volume = 10 ml = 10 x 10^ -3 L = 0.01 L
we have formula Number of moles = M x V
hence number of moles of NaOH = 0.5 x 0.01 = 0.005 = 5 x 10^-3
What is the moles of NaOH added when the concentration is 500mL and the volume of...
Volume NaOH added Moles of NaOH added 0.00010 Concentration of NaOH-0.1 M Concentration of HC H10.-01 M a) What is the pH at equivalence point? b) What is the volume of N hat equivalence point? c) Moles of NOH at the equivalence point? d) Moles of HCHO at equivalence point? e) Find K. of HC HO Find pk of HC HO 000220 ellas
Data and Calculations: concentration of NaOH: 0.125M Initial volume of NaOH: 26.0ml Final volume of NaOH: 39.7 Volume of NaOH: ? Moles of NaOH added: ? Moles of acetic acid: ? Volume of vinigar: 40.0 concentration of acetic acid: ?
calculate rad
Initial reading Volume NaOH added Calculation of Molar Concentration Moles KHC HẠO, 2.45 lb .60.40 m. 28.20 27.5027155 31.05 mL .5902 .6405 5863 oua 3 204.23 204.23 20423 3002889 .003136.281.00212 moi 002869003136 002871.0027 mol 28.20 87.50 27.55 31.05 1 01020 01140.1042.0879 m oloa Moles NaOH average , .006906 Volume NaOH added Molarity NaOH next page Average molarity NaOH Precision as RAD ppt F18 1.1020-1020/39/1 1140 - 1020 1.1042- + 1.0879-1020t
A 500mL solution of 0.40M HC2H3O2 is made. What mass of NaOH must be added to have a buffer with a pH of 5.20? Ka of Acetic Acid is 1.8*10^-5.
Volume NaOH added Moles of NaOH added pH (mL) 0 2.89 0 3.18 0.00010 0,00020 3.18 0.00030 3 3.42 3.56 4 0.00040 0.00050 5 3.67 Concentration of NaOH-0.1 M Concentration of HCHO-0.1 M 6 3.73 0,00060 0,00070 7 3.89 0,00080 8 3.99 9 4.07 0.00090 What is the pH at equivalence point? What is the volume of NaOH at equivalence point? a) 10 4.14 0.00100 b) Moles of NaOH at the equivalence point? Moles of HC:H0 at equivalence point? 11...
Concentration of HCI is 0.09655 M. Concentration of NaOH is 0.100 M. a) What is the pH at equivalence point? b) Moles of HCl at equivalence point? c) Moles of NaOH at equivalence point? d) Volume of NaOH at equivalence point? Volume NaOH added (mL) pH Moles of NaOH added 0.89 0.89 0.00010 0.89 0.00020 0.90 0.00030 0.91 0.00040 0.93 0.00050 0.94 0.00060 0.96 0.00070 0.98 0.00080 1.01 0.00090 1.03 0.00100 1.06 0.00110 LOS 0.00120 1.11 0.00130 1.15 0.00140 1.19...
I need help figuring out the moles of KHP and Concentration of
NaOH for the values in the data table
Chemistry 201 Standardization of NaOH - ONLINE College of the Canyons 4. Complete Data Table 1. The neutralization reaction between KHP and NaOH is: KHCH40 (aq) + NaOH(aq) 4 KNaC,H,O4(aq) + H200) Trial 2 Trial 3 39. 143 mL 39.157 ML Data Table 1. Standardization of NaOH solution Trial 1 Volume of 0.500 M KHP, ml 139.163 mL Buret reading...
What is the concentration of Cu2+ when 0.025 moles of copper (II) sulfate are added to one liter of a solution that is 1.0M CN-? Cu2+ + 4CN- —> <— Cu(CN)4 2-
How to caculate moles of NAOH added and the molarity of
unknown acid
Sheets (To be attached to your lab report. Recopy if messy) Data Sheets 1 by Unknown Letter oticMolarity of NaOH (mol/L).o Volume of unknown acid (mL.) A. Initial volume0.5 m Run 1 Run 2 Run 3 NaOH 206 20 64 m 33. 35 w B. Final Volume NaOH NaOH volume added (subtract B - A) Moles NaOH added Analysis: Molarity of unknown acid (assuming the acid is...
When a small volume of NaOH solution is added to an acetate/acetic acid buffer system, which of the following occur? Choose one or more: The final volume of the solution will increase The pH will increase. The pH will stay the same. The concentration of acetate will increase. The pH will decrease. The concentration of acetic acid will decrease.