Question

the amount up oL 6- If 12.00 L of a 6.00 M HNO3 solution needs to be diluted to 0.750 M, what will be its final volume? 8- If 1.00 L of an LiOH solution is boiled down to 164 mL and its initial concentration is 0.00555 M, what is its final concentration? 10 How much water must be added to 1.55 L of 1.65 M Sc(NO3)3(aq) to reduce its concentration to 1.00 M?

Answer 1

6. Using the Molarity equation Miv - M₂ V₂ Initial) (final) Given Initial Molarity of HNO₃ = 6.00M Initial volume of HNO2 = 12.00€ Final Molarity of HNO₂ = 0.750M Final Volunis =' ? ., 6x12 = 0750x V2 v2 = 6x12 = 96L C 0.750 8. Here also we use Molarity equation, Initial volume of Lion= 100% Initial concentration Molari'y = 0.00555M final concentration / Molarity = ? final volume = 164ml or 0.164L. M, V = M2 V2 (Initial) (final 0.00555x1 = M₂ x 0.164 M₂ 2 0.00555 0.164 M₂ = 0.0338M

10. M. V= M₂ V2 1.55x 1.65 = 1.00x V₂ (Sc (NO3) (water) ₂ = 1.55 +1.65 V = 2.5575 Water must be added to SC (NO₂) to reduce its concentration will be = 2.5575-1-55 = 1.0075L 8. needed to obtain Volume of 3.99M 11 Soy asl mole of the say = ? Molarity = No. of moles of solute Volume of solution in L 4,61 3.99M= Volume 4.61 Volume = 3.99 I Volume 1.152/