Please show work to make sure I understand the material! If possible some notes or tricks!
Thank you in advance! I appreciate you!
Please show work to make sure I understand the material! If possible some notes or tricks!...
Please show work to make sure I understand the material! If
possible some notes or tricks!
Thank you in advance! I appreciate you!
104 Find Vo = 5 mA, R = 7 k2, and the open-loop voltage gain, A = as a function of Rx, use x for Rx. I Also indicate the range for Rx for the linear operation of the op-amp. R 20V 4k2 1k2 Vo -20V Rx Is 2502 Vo(x) V <Rx Scroonchot
104 Find Vo =...
Please show work to make sure I understand the material! If
possible some notes or tricks!
Thank you in advance! I appreciate you! Please do not round
numbers so I can follow the problem easier.
104 Find Vo = 5 mA, R = 7 k2, and the open-loop voltage gain, A = as a function of Rx, use x for Rx. I Also indicate the range for Rx for the linear operation of the op-amp. R 20V 4k2 1k2 Vo...
Electronic Circuit Design and Analysis
Please show work to make sure I understand the material! Thanks
in advance!
2. Consider the JFET self-bias network shown VDD 10V RD 5002 ID Vos loss 20 mA VGs RG 0.75 ΜΩ Rs 250Ω a) Using a graphical approach, determine VGs and ID. b) Repeat, assuming that Rs has been doubled to 500 S2 but all other aspects of the circuit remain unchanged. Does doubling Rs cause the drain current to decrease to one...
please show all steps. I have the answers. I am not sure how
to do the work to get them. i will give thumbs up for whomever does
this
Below are the correct answers:
Vba=6.300
Vb =9.600
Vd=6.6207
Ved=2.4
Ve=6.1
w3=2.100
w4=6.207
w5=1.600
w6=4.3571
2) For the system below, va -10 in/s to the right and a-2 in/s to the left at the provided position. CT) 1.0" BD = 1 .05" BC = 1.45" ED 1.5" FE = 1 .4"...
please show work when possible so that I may better
understand. Thank you.
x=L The rail gun consists of two thick conducting rails connected to a power supply and there is a magnetic field assumed to be uniform and constant in the direction shown. A short conducting bar that is to be (or carry) the projectile is placed across the bars at x -0. The current flows through the bars as shown. The magnetic force on the bar causes it...