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Problem 5: Reading from a graph This is a snapshot of a harmonic wave y-A cos [2π (x-T)| taken at a time t -3s. A COS 2T y(m) 2 a) What is the amplitude A, wavelength A, period T (if there are more options, pick the biggest value) and the di- rection of the propagation of X(m) 4 the wave b) What is the speed of the prop- agation of the wave given λ and l from previous question! 2

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Answer #1

For a harmonic wave graph, the

Wavelength = distance between two identical points on the wave. (Here, at x=1 and at x=3m)

Amplitude= maximum distance of peak from the x axis. Therefore, here A=2m

Now since we know the equation of the harmonic wave and the values of A and wavelength at t=3s we can put those values in the eauaequaand find out the value of Time period i.e. T.

b) speed of propagation of a wave= wavelength/ time. Therefore we can put those values and find the speed

0.33m/4

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