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16 Problem #1 (65 pts) Consider the regenerative Rankine Cycle steam power plant below. The isentropic efficiency of the turb
16 Mib Determine the fractions of the total flow used for regeneration (M/M,) and through turbine #2 (M,/M,). (See figure) Yo
16 Mib Determine the fractions of the total flow used for regeneration (M/M,) and through turbine #2 (M,/M,). (See figure) Yo
16 #le. Calculate the total turbine work (both turbines) per pound mass of steam through the boiler (/M,) #1d. Derive and exp
c(T,-T) clT,-T)+v(p- P) incompressible substances (liquids) cln Law equations are written according to the convention that he
16 Problem #1 (65 pts) Consider the regenerative Rankine Cycle steam power plant below. The isentropic efficiency of the turbines is 0.85, and that for the pumps is 0.75. A property table is given which defines some key states to save you time. You do not have to fill in this table. M, Boiler/Superheater TI FWH Reheat PI M2 2 T2 Condenser P2 4 5 (quality) (ft/lbm) S h V P (psia) T (F) State (Btu/lbm- R) 1.5598 (Btu/lbm) 1474.1 1000 2000 140 2 1.8823 1531 1000 140 3 2,008 1124.1 69.7 142.4 1 4 0.1326 0.0000 101.8.7 1 5 0.1328 70.25 101.8 140 0.0000 0.5074 325 353.1 140 7 2000 8
16 Mib Determine the fractions of the total flow used for regeneration (M/M,) and through turbine #2 (M,/M,). (See figure) You must show the derivations.
16 Mib Determine the fractions of the total flow used for regeneration (M/M,) and through turbine #2 (M,/M,). (See figure) You must show the derivations.
16 #le. Calculate the total turbine work (both turbines) per pound mass of steam through the boiler (/M,) #1d. Derive and expression for the actual pump work (Btu/lbm through P1) for pump #1 and then calculate its value. Then calculate the actual value for hs.
c(T,-T) clT,-T)+v(p- P) incompressible substances (liquids) cln Law equations are written according to the convention that heat is entering the system, work is stem. #1e Calculate the total heat input per pound mass of steam through the boiler,
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Answer #1

CaNen, psia, Ti0oF, Sia5598 Bbm°R 2000 P2= 40Psia, sen hropic expannon un tuabund, Si252= (-5598 Bu/bn P2=140psa, S32 5T51 Bb(b) By enengy balane urj PwH, LyW ма - м- мз M h2hatM3 he = myh7 MI Ch-h2) M3h6-h2) hT-h2 h-h2 325-1180.45 To-25-180 25 M3 0.WAhg-h7 dp dp Pr- P7 Qudog3 WpI O.01802 x 1860 x ~anvenun fachy 5.4039 WPI 2 6202 Btu/ Lb 325 Bhu/Cb. 6.202 wgaduws 8-269 Bu/

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