2. A force F(x, y,z) -20i 6j 20k]N is applied to the end of a rigid...
A force F⃗ = 2.00 N i⃗ + 3.10 N j⃗ is applied at the point x = 3.20 m , y = 0.00 m . Find the torque about the origin due to the force F⃗ . Give the x, y, and z components. What is the torque due to the same force, applied at the same location, about the point x = -1.00 m , y = 3.10 m ? Give the x, y, and z components.
1. (a) Force F = -21 - 4 (N) is applied to a metal bar in the x-y plane with one end of the bar at the origin. The point on the bar of application of the force is (x - 2m, y m). Use the position vector (1) of the point of action of the force to find the magnitude and direction of the torque. Hint: Employ method of determinant to find cross product (6pts) Show working (2pts) Magnitude...
A metal bar is in the xy-plane with one end of the bar at the origin. A force F =( 6.39 N )i +( -3.16 N )j is applied to the bar at the point x = 2.29 m, y = 3.19 m.A) What is the position vector r⃗ for the point where the force is applied?Enter the x and y components of the radius vector separated by a comma.*B) What is the magnitude of the torque with respect to...
A metal bar is in the xy-plane with one end of the bar at the origin. A force F =(6.12 N )i+(-3.27 N )j is applied to the bar at the point x = 2.07 m, y = 3.02 m. Part A What is the position vector for the point where the force is applied?Part B What is the magnitude of the torque with respect to the origin produced by F?
1. (a) Force F = -21 - 4 (N) is applied to a metal bar in the x-y plane with one end of the har at the origin. The point on the bar of application of the force is (x = -2m, y - 4m). Use the position vector (1) of the point of action of the force to find the magnitude and direction of the torque. Hint: Employ method of determinant to find cross product (6pts) Show working px...
solve this using matlab
please
Task 3: [25 marks] Consider the force applied at the end of the lever. If you apply a force to the lever close to the pivot point, the effect is different than if you apply the force further out on the lever. That effect is called Moment given by the formula; M = r *F Here r and F are the position vector and the force vector respectively. ř = ai + bj +ck F...
A force F⃗ of magnitude F making an angle θ with the x axis is
applied to a particle located along axis of rotation A, at
Cartesian coordinates (0,0) in the figure. The vector F⃗ lies in
the xy plane, and the four axes of rotation A, B, C, and D all lie
perpendicular to the xy plane.
A particle is located at a vector position r⃗ r→r_vec with
respect to an axis of rotation (thus r⃗ r→r_vec points from...
To understand two different techniques for computing the torque on an object due to an applied force.Imagine an object with a pivot point p at the origin of the coordinate system shown (Figure 1). The force vector F⃗ lies in the xy plane, and this force of magnitude F acts on the object at a point in the xy plane. The vector r⃗ is the position vector relative to the pivot point p to the point where F⃗ is applied.The torque on the...
A force F = 1.8 i + 2.5 j N is applied at the point x = 3.0 m, y = 0 m. (a) Find the torque about the origin. k N
A force F = 61 N i acts on an object
at a point (x0, y0) = (6.2 m, 4.7
m) as shown in the figure. What is the magnitude of the
torque generated by this force about the origin?
What is the magnitude of the torque generated by this force
about the point (x, y) = (2.9 m, 1.6 m)?
Suppose the object is free to rotate about the z axis. If the
object has a moment of inertia...