H = [4
H0f(CO2)
+ 2
H0f(H2O)]
- [2
H0f(C2H2)
+ 5
H0f(O2)]
H = [4(-393) +
2(-242)] - [2(227) + 5(0) ]
H = [4(-393) +
2(-242) ] - [2(227)]
H = 4(-393) +
2(-242) - 2(227)
H = - 1572 - 484
- 454
H = - 2510
kJ
The heats of formation, AH in are shown in the table. What is AH in kJ...
The heats of formation, AH in are shown in the table. What is AH in kJ for the reaction 2C2H2 502(8) 4CO2(8) 2H20(8) AH ? AH? Compound C2H2(8) H20(8) CO2le) +227 -242 -393 (A)-4 x 94.0-2x 57.8 54.2 (B) -4 x 94.0-2 x 57.8 -54.2 (C) -4 x 94.02 x 578 -2 x 54.2 (D)4 x 94.0 2x 57.8 + 2 x 54.2
2. Given the following heats of formation, calculate AH for the reaction 2 CO(g) + 5 H2(g) → C2H6 (g) + 2 H2O(g) Compound AH°F (kJ/mol) Compound AH°F (kJ/mol) 52.28 C₂H6 (8) -84.68 C2H4 (8) -393.5 CO2(g) -241.8 H2O(g) -285.9 CO(g) -110.5 H2O(1)
for the following reaction. CH3OH) -238 + H2(g) Given the standard heats of formation for the following compounds, calculate Al CH4() + H2O(g) -75 -242 AH(k/mol) a. +79 kJ b..79 kJ 6. +594 kcal d.-405k ..594 kcal
Tutored Practice Problem 10.6.2 COUNTS TOWARDS GRADE Calculate enthalpy change using standard heats of formation. Using the standard heats of formation that follow, calculate the standard enthalpy change for the following reaction. H2S(g) 2H20(I) »3H2(g) +SO2(g) AH rxn kJ Species AHf(kJ/mol H2S(g) -20.6 H2O(D -285.8 SO2(g) -296.8 Check & Submit Answer Show Approach
help asap
3. Calculate the standard enthalpy change, Hº, for the following reaction using standard enthalpies of formation. (1 point) 2C2H2(g) + 502(g) → 4CO2(g) + 2H20(1) Standard Enthalpies of Formation AH for C2H2(g) = +226.7 kJ/mol AHfor CO2(g) = -393.5 kJ/mol AH for H2O(l) = -285.8 kJ/mol
C Using the heats of formation below, calculate the heat of reaction for the following reaction: CH4(g) + H2O(g) → C2H5OH(E) AH® (kJ/mol) C2H4(g) 52.26 H2O(g) -241.8 C2H5OH(E) -235.1 kJ d Using the heats of formation below, calculate the heat of reaction for the following reaction: Fe2O3(s) + 2Al(s) - A1203(s) + 2Fe(s) AH(kJ/mol) Fe2O3(s) -824.2 Al(s) 0 Al2O3(s) -1676 Fe(s) 0 KJ
1.
Balance the following equation in acid:
2. Consider the following reaction; how many Kj are released
for 1 mol c2h2
3. Calculate delta H for the reaction
1. Balance the following equation in acid: 2. Consider the following reaction: 2C2H2(g)+502(g)- 4C028)+2H20(g) AH--2511 kJ How many kJ are released for 1 mol C2H2? 3. Given the following data: 3C(gr) + 4H2 (g) C3Hs(g) AH--103.85 kJ C(gr) + O2(g)-Co2(g) AH--393.67 kJ 2H2(g) +02(g)-> 2H20() ΔΗ-,-571.5 kJ Calculate AH for the following...
2.5 points Save Answer Given the following standard heats of formation: NH3 () --45.90 kJ/mol, O2(0) Okmol. H20 (3) --241.83 kJ/mol, and NO () -90.30 kJ/mol, the enthalpy of reaction would be Be careful of significant figures. 063.pdf Moving to another question will save this response 4 NO (8) + 6 H2O (8) 4 NH3 (8) + 502
Given the following equations and AH' values: C(s) + O2(g) + CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) - H20 (1) AH = -285.8 kJ 2C2H2 (8) + 5O2(g) + 4CO2(g) + 2H20 (1) AH'= -2598 kJ Determine the heat of reaction (in kJ) at 298 K for the reaction: 2C(s) + H2(8) C2H2 (8) 0-136.8 0-219.8 0-109.9 O-167.1 +226.2
5. Using standard heats of formation, calculate AH for 4 FeO (s) + O2(g) → 2 Fe2O3 (s) AH1 of FeO (s) = -272.0 kJ/mol AHºf of Fe2O3 (s) = -825.5 kJ/mol 3. Given 3 C (s) + 4 H2(g) → C3H8 (9) AH = -103.85 kJ/mol C(s) + O2(g) + CO2(g) AH = -393.5 kJ/mol H2 (g) + 12 O2(g) → H2O (1) AH = -285.8 kJ/mol find AH for C3H8 (g) + 5 O2(g) → 3 CO2 (g)...