The heats of formation, AH in are shown in the table. What is AH in kJ...
The heats of formation, AH in are shown in the table. What is AH in kJ for the reaction 2C2H2+502(g)4CO28)+2H20(8) AH=? Compound C2H28) H2O(8) CO2LB) +227 -242 -393 (A) -4 x 94.0-2x 57.8 54.2 (B) -4 x 94.0-2x 57.8 54.2 (C) -4 x 94.0-2x 57.8-2x 54.2 (D) 4x 94.0 2x 57.8 + 2 x 54.2
Given the following equations and AH' values: C(s) + O2(g) + CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) - H20 (1) AH = -285.8 kJ 2C2H2 (8) + 5O2(g) + 4CO2(g) + 2H20 (1) AH'= -2598 kJ Determine the heat of reaction (in kJ) at 298 K for the reaction: 2C(s) + H2(8) C2H2 (8) 0-136.8 0-219.8 0-109.9 O-167.1 +226.2
Calculate the value of AH° for the reaction 2 C2H2 () + 502 () 4002) + 2 H20 (1) given the following thermochemical equations: AH° = - 242 kJ AH° = - 394 kJ H2(g) + 4202) → H20 (8) C(s) + O2(%) + CO2(8) 2 C(s) + H2(g) → C2H2 (6) H20 () → H30Ⓡ AH° = +227 kJ AH° = +44 kJ TO - 907 kJ 0 - 2602 kJ 0 - 2514 kJ - 1694 kJ
help asap 3. Calculate the standard enthalpy change, Hº, for the following reaction using standard enthalpies of formation. (1 point) 2C2H2(g) + 502(g) → 4CO2(g) + 2H20(1) Standard Enthalpies of Formation AH for C2H2(g) = +226.7 kJ/mol AHfor CO2(g) = -393.5 kJ/mol AH for H2O(l) = -285.8 kJ/mol
all 3. Calculate the heat released (kJ) in the reaction of 1.35L of acetylene (C2H2) and 0.235L of hydrogen gas at STP to form ethane gas as determined by the following equation: C2H2(g) + 2H2() → C2H6(g) Given: 2C2H2(g) +502(g) + 4CO2(g) + 2H20(g) 2C2H.(g) + 702(g) → 4CO2(g) + 6H20(g) 2H2(g) + O2(g) → 2H2O(g) AH = -2320 kJ/mol AH = -3040 kJ/mol AH = -572 kJ/mol
a Using the heats of formation below, calculate the heat of reaction for the following reaction: C2H2(g) + 5/202(2)→ 2C02() +H20() AH® (kJ/mol) C2H2(g) 226.7 O2(g) 0 CO2(g) -393.5 H20(-285.8 kJ Submit b Using the heats of formation below. calculate the heat of reaction for the following reaction: PC13(2) + Cl2(2)→ PC15(e) AH(kJ/mol) PC13(g) -306.4 Cl2(E) 0 PC1s() -398.9
1. Balance the following equation in acid: 2. Consider the following reaction; how many Kj are released for 1 mol c2h2 3. Calculate delta H for the reaction 1. Balance the following equation in acid: 2. Consider the following reaction: 2C2H2(g)+502(g)- 4C028)+2H20(g) AH--2511 kJ How many kJ are released for 1 mol C2H2? 3. Given the following data: 3C(gr) + 4H2 (g) C3Hs(g) AH--103.85 kJ C(gr) + O2(g)-Co2(g) AH--393.67 kJ 2H2(g) +02(g)-> 2H20() ΔΗ-,-571.5 kJ Calculate AH for the following...
Calculate the standard enthalpy of reaction for the reaction below, by following the directions in Part (a) and Part (b). 2C2H2(8) + 502(8) - 4CO2(g) + 2H2O(g) AH = ? • Part(a): Write standard enthalpy of formation reactions for C2H2, CO2, and H20. Write the corresponding standard enthalpy of formation value next to each equation. • Part(b): Manipulate these equations and calculate the enthalpy of reaction.
2. Given the following heats of formation, calculate AH for the reaction 2 CO(g) + 5 H2(g) → C2H6 (g) + 2 H2O(g) Compound AH°F (kJ/mol) Compound AH°F (kJ/mol) 52.28 C₂H6 (8) -84.68 C2H4 (8) -393.5 CO2(g) -241.8 H2O(g) -285.9 CO(g) -110.5 H2O(1)
2.5 points Save Answer Given the following standard heats of formation: NH3 () --45.90 kJ/mol, O2(0) Okmol. H20 (3) --241.83 kJ/mol, and NO () -90.30 kJ/mol, the enthalpy of reaction would be Be careful of significant figures. 063.pdf Moving to another question will save this response 4 NO (8) + 6 H2O (8) 4 NH3 (8) + 502