The moment of inertia of the helicopter’s rotor is 420 slug-ft2. The rotor starts from rest. At t = 0, the pilot begins advancing the throttle so that the torque exerted on the rotor by the engine (in ft-lb) is given as a function of time in seconds by T = 200t.
(a) How long does it take the rotor to turn ten revolutions?
(b) What is the rotor’s angular velocity (in rpm) when it has turned ten revolutions?
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