Problem

The following are average operating data from a conventional activated-sludge secondary: w...

The following are average operating data from a conventional activated-sludge secondary: wastewater flow = 7.7mgd, volume of aeration tanks = 300.000 ft3 = 2.24 mil gal. influent total solids =600mg/l, influent suspended solids - 120 mg/l, influent BOD = 173 mg/l. effluent total solids = 500 mg/l, effluent suspended sOlids = 22 mg/l. effluent BOD = 20 mg/l, mixed-liquor suspended solids = 2500 mg/l, re circulated sludge flow = 2.7 mgd, waste sludge quantity = 54,000 gpd, and suspended solids in waste sludge = 9800 mg/l. Based on these data, calculate the following: aeration period; BOD loading in lb/1000 ft'/day; F/M ratio in lb BOD/day/lb MTSS: total solids, suspended solids, and BOD removal efficiencies: sludge age; and return sludge rate.

Step-by-Step Solution

Request Professional Solution

Request Solution!

We need at least 10 more requests to produce the solution.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the solution will be notified once they are available.
Add your Solution
Textbook Solutions and Answers Search