Problem

The Henry’s law constant for the solubility of oxygen in water is Air is 21 mol% oxygen...

The Henry’s law constant for the solubility of oxygen in water is Air is 21 mol% oxygen.

(a) How many grams of oxygen can be dissolved in one liter of a trout stream at 12°C (54°F) at an air pressure of 1.00 atm?

(b) How many grams of oxygen can be dissolved per liter in the same trout stream at 22°C (72°F) at the same pressure as in (a)?

(c) A nuclear power plant is responsible for the stream’s increase in temperature. What percentage of dissolved oxygen is lost by this increase in the stream’s temperature?

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