Problem

For the network of Fig. 2.171 sketch vo and iR.FIG. 2.171

For the network of Fig. 2.171 sketch vo and iR.

FIG. 2.171

Step-by-Step Solution

Solution 1

Refer to Figure \(2.171\) in the textbook.

The Silicon diode (Si) starts conducting when the output voltage \(v_{o}\) is \(0.7 \mathrm{~V}\).

Calculate the input voltage.

\(v_{o}=\frac{1 \mathrm{k} \Omega v_{i}}{1 \mathrm{k} \Omega+1 \mathrm{k} \Omega}\)

\(0.7 \mathrm{~V}=\frac{1 \mathrm{k} \Omega v_{i}}{1 \mathrm{k} \Omega+1 \mathrm{k} \Omega}\)

\(v_{i}=1.4 \mathrm{~V}\)

When the input voltage \(v_{i} \geq 1.4 \mathrm{~V}\), the Silicon (Si) diode is in ON state and the output voltage \(v_{o}\) is \(0.7 \mathrm{~V}\).

When \(v_{i}<1.4 \mathrm{~V}\), the Silicon (Si) diode is off.

Calculate the level of the output voltage.

$$ \begin{aligned} v_{o} &=\frac{1 \mathrm{k} \Omega}{1 \mathrm{k} \Omega+1 \mathrm{k} \Omega} v_{i} \\ &=0.5 v_{i} \end{aligned} $$

Calculate the output voltage for an input voltage of .

Draw the output voltage waveform.

C:\Users\ashivam\AppData\Local\Microsoft\Windows\INetCache\Content.Word\f2.jpg

Calculate the voltage across the \(1 \mathrm{k} \Omega\) resistor for positive half cycle.

$$ \begin{aligned} v_{R} &=v_{\max }-0.7 \mathrm{~V} \\ &=10-0.7 \\ &=9.3 \mathrm{~V} \end{aligned} $$

Calculate the current flowing through \(1 \mathrm{k} \Omega\) resistor for positive half cycle.

$$ \begin{aligned} I_{R} &=\frac{v_{R}}{R} \\ &=\frac{9.3 \mathrm{~V}}{1 \mathrm{k} \Omega} \\ &=9.3 \mathrm{~mA} \end{aligned} $$

Calculate the maximum current for the negative peak point .

Draw the waveform for current, .

Picture 4

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