Determine vo for each network of Fig. 2.176 for the input shown.FIG. 2.176

Now for \(v_{i}=-0.7 \mathrm{~V}\) the output voltage is \(v_{o}=(-0.7+0.7) \mathrm{V}=0 \mathrm{~V}\)

Hence, for \(v_{i}=-0.7 \mathrm{~V}\) the output voltage \(v_{o}\) is \(0 \mathrm{~V}\)

The output voltage waveform is given as follows.

Figure 1

Refer to the Second circuit diagram in Fig. 2.176 in the textbook.

Now for \(v_{i} \leq 8 \mathrm{~V}\) ensures the Silicon (Si) diode is forward biased and the output voltage is given

as:

$$ v_{o}=v_{i}-8 \mathrm{~V} $$

For the input voltage \(v_{i}=8 \mathrm{~V}\) the output voltage \(v_{o}\) is given as:

$$ \begin{aligned} v_{o} &=v_{i}-8 \mathrm{~V} \\ &=8 \mathrm{~V}-8 \mathrm{~V} \\ &=0 \mathrm{~V} \end{aligned} $$

Hence, input voltage \(v_{i}=8 \mathrm{~V}\) the output voltage \(v_{o}\) is \(0 \mathrm{~V}\)

For the input voltage \(v_{i}=-20 \mathrm{~V}\) the output voltage \(v_{o}\) is given as:

$$ \begin{aligned} v_{o} &=v_{i}-8 \mathrm{~V} \\ &=-20 \mathrm{~V}-8 \mathrm{~V} \\ &=-28 \mathrm{~V} \end{aligned} $$

Hence, input voltage \(v_{i}=-20 \mathrm{~V}\) the output voltage \(v_{o}\) is \(-28 \mathrm{~V}\).

The output voltage waveform is given as follows.

Figure 2