Suppose the sample in Exercise 6.80 has produced p̂ =.84 and we wish to test H0: p =.9 against the alternative Ha: p < .9
a. Calculate the value of the z statistic for this test.
b. Note that the numerator of the z statistic (p̂ − p0 =.84 −.90 = −.06) is the same as for Exercise 6.80. Considering this, why is the absolute value of z for this exercise larger than that calculated in Exercise 6.80?
c. Complete the test, using a =.05, and interpret the result.
d. Find the observed significance level for the test and interpret its value.
We need at least 10 more requests to produce the solution.
0 / 10 have requested this problem solution
The more requests, the faster the answer.