Exercise 29 outlines how energy may be extracted by transferring an electron from an atom that easily loses an electron to one with a large appetite for electrons, then allowing the two to approach, forming an ionic bond.
(a) Consider separately the cases of hydrogen bonding with fluorine and sodium bonding with fluorine.
In each case, how close must the ions approach to reach "break even," where the energy needed to transfer the electron between the separated atoms is balanced by the electrostatic potential energy of attraction? The ionization energy of hydrogen is 13.6 eV, that of sodium is 5.1 eV, and the electron affinity of fluorine is 3.40 eV.
(b) Of HF and NaF, one is considered to be an ionic bond and the other a covalent bond. Which is which, and why?
We need at least 10 more requests to produce the solution.
0 / 10 have requested this problem solution
The more requests, the faster the answer.