Alright Dude, If that worked for you... dont forget to give THUMBS UP.(that will work for me!)
If I missed something feel free to leave a comment.
atleast before giving downvote.
and, Thanks for using homeworklib- Smarter way to study.
(3%) Problem 17: An evacuated tube uses a potential difference ofΔν= 0.22 kV to accelerate electrons,...
(13%) Problem 2: In an evacuated tube electrons produce X-rays by accelerating from rest through a voltage of 0.41 kV and striking a copper plate. Nonrelativistically, what would be the maximum speed of these electrons, in meters per second? VE cos0 cotan0 asin acos0 tancotan sin0 cosh)tanh)cotanh0 o Degrees Radians sin0 HOME 4 5 6 12 3 0 END 4o BACKSPACE DEL CLEAR
(20%) Problem 3: Acandle (h, = 0.22 m) is placed to the left of a diverging lens (f= -0.074 m). The candle is do = 0.12 m to the left of the lens 25% Part (a) Write an expression for the image distance, dj. Grade Summary 0% Deductions Potential 100% ( 0 Submissions 7 НОМЕ Attempts remaining: 5 (0% per attempt) detailed view AA d 4 5 6 а f 3 j k 0 END VO BАСKSРАСЕ P S DEL...
Part A and B on both please. Will upvote.
A conducting sphere of radius rı 0.22 m Problem 7: a23 m has a total charge of e-2-pC. A second uncharged conducting (10%) sphere of radius to their size. links to the first by a thin conducting wire. The spheres are separated by an enormous distance compared 50% Part (a) what is the total charge on sphere two 02 after they are connected, in coulom Grade S Deductio Potential sin() |...
(10%) Problem 7: An object of height h, is placed a distance do in front of a converging lens of focal length f. 50% Part (a) Write an equation for the image distance using variables from the problem statement. d; =(-d. f)(f-do) Correct! > * 50% Part (b) Write an equation for the height of the image using variables from the problem statement. h;= (- do fh, d. (f-do) Grade Summary Deductions 3% Potential 97% B y d. h. f...
(5%) Problem 17: An object is located a distance de = 5.4 cm in front of a concave mirror with a radius of curvature r = 20.3 cm. A 33% Part (a) Write an expression for the image distance, d;. di = 1 Grade Summary Deductions 0% Potential 100% B 0 ( 7 8 9 HOME | 1| 4 5 6 * 1 2 3 + - 0 . END VO BACKSPACE DEL CLEAR Submissions Attempts remaining: 10 (0% per...
(10%) Problem 3: A research-level Van de Graaff generator has a 2.05 m diameter metal sphere with a charge of 5.1 mC on it. 33% Part a) What is the potential near its surface in MV? Assume the potential is equal to zero far away from the surface. Grade Summary Deductions 8% Potential V- 4.47-I 92% sin0 cotanasin acos atanacotan sinhO cosh0 tanhOcotanh0 78 9 HOME Submissions Attempts remaining:6 (2% per attempt) detailed view 0 END 2% 2% 2% 2%...
(17%) Problem 9: An object of height 2.2 cm is placed 29 cm in front of a diverging lens of focal length 16 cm. Behind the diverging lens, and Il cm from it, there is a converging lens of the same focal length. * 50% Part (a) Find the location of the final image, in centimeters beyond the converging lens. s"= 22.89 Grade Summary Deductions Potential HOME sin cos t an cotan asin) acos atan acotan() sinh Cosh0 tanh) Coanh)....
(17%) Problem 6: A 65-kg skydiver jumps out of an airplane and falls 490 m, reaching a maximum speed of 59 m/s before opening her parachute. Randomized Variables m= 65 kg h= 490 m v=59 m/s 50% Part (a) How much work, in joules, did air resistance do on the skydiver before she opened her parachute? Grade Summary Deductions 0% Potential 100% ( | E sin() cos() tan() cotan asin() acos atan) acotan sinh) cosh tanh cotanh Degrees O Radians...
(20%) Problem 4: The shadow of a pendulum cast on a flat board moves on a straight line. By placing the x-axis on the straight line with the origin at the middle of the total path, the x-coordinate of the shadow is given by the following function: x(t) = 49cos(st), where t is in seconds and x is in centimeters. 25% Part (a) Find the speed, in centimeters per second, of the shadow at t = 1/4 s. v =...
For part c, I tried -242 and +242 and I still got it
incorrect.
(20%) Problem 4: The shadow of a pendulum cast on a flat board moves on a straight line. By placing the x-axis on the straight line with the origin at the middle of the total path, the x-coordinate of the shadow is given by the following function: x(t) = 49cos(st), where t is in seconds and x is in centimeters. 25% Part (a) Find the speed,...