Question

5. An ideal gas (y= 1.4) Volume 2 m' and if is compressed to 4x10 Pa adiabatic at Volume 0.5 m². Calculate the work in that process.

Answer 1

Hi,

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We know that, Pressure-volume relation in a adiabatic process is given by,

PiV' = P2V,

We have,

Initial volume,

V1 = 2 m

Final volume,

V2 = 0.5 m

Final pressure,

P = 4 x 106 Pa

Therefore, Initial pressure is given by,

P= P2 (**)' = 4 x 106 Pax (0.5 m) 2 m3

:: P = 5.7435 x 106 Pa

Therefore, Work done is given by,

:: W = 0 - (P3.V2 – P1.V1)

:: W = (4 x 106 Pa x 0.5 m3 – 5.7435 x 106 Pa x 2 m)

::W = 851301.645 J (-0.4)

::W = -2128254.113 J

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