Question

Glucose, CH20, is used as an energy source by the human body. The overall reaction in the body is described by the equation CH, (aq) +60,g) – 6CO,() + 6H,O) Calculate the number of grams of oxygen required to convert 13.0 g of glucose to CO, and H, 0. mass of O, mass of 0, : Calculate the number of grams of CO, produced. mass of CO,

Answer 1

The answer to the question is given below:

CHin Oscaq) + 602 (9) — 6002.() +6720(1) '84 c5 91 mol produces - 16X 44.01 = 264.06)8/mol of CO2 of China Iglmal of G H 2 O will produce = 264.06 g/mol of co, 180.15 13g mol of CSHIDDG will produce = 264.06x13 180.15 = 19.05g/mol of CO2 264.06 g/mol is produced by (16*6 = 96)g/mol of on 19.05g/mol will be produced b = 96 x 19.05 - 264.06 = 6.92 g/mol of O₂ @) Mass of O2 required to convert 139 of glucose to coz and HD - = 6.92g (b) Mass of CO₂ produced = 19.05g