Question

Glucose, C₆H₁₂O₆, is used as an energy source by the human body. The overall reaction in the body is described by the equation

C₆H₁₂O₆(aq) + 6O₂(g) — 6CO₂(g) + 6H₂O(1) 

Calculate the number of grams of oxygen required to convert 38.0 g of glucose to CO₂, and H₂O. 

mass of O₂ = _______ g 

Calculate the number of grams of CO₂, produced. 

mass of CO₂ = _______ g 

Answer 1

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C6H12O6 (aq) + 602191 6602191 + 6H2Orel 180.16 18.0 Molar may ringlmol) 3210 44.0 I mole of glucose react with 6 moles of O2 180.10g of Cothia o react with 6X3210 g of O2 380g of Cotia Uo react with Or 68320 9 x 38.09 180.169 = 40.5 g 02 Hence, 40.5g of oxygen will be required I mole of C6H12O6 180.16g of Colth2 Oc produce 38.0 g of Cotia Oo produce produce 6 moles of CO2 6x44.09 of CO2 CO2 = 6X44.09. 180.169 = 5517 g CO2 Hence, 55.7g of con will be produced