Question

Glucose, C 6 H 12 O 6 , is used as an energy source by the human body. The overall reaction in the body is described by the equation C 6 H 12 O 6 ( aq ) + 6 O 2 ( g ) ⟶ 6 CO 2 ( g ) + 6 H 2 O ( l ) Calculate the number of grams of oxygen required to convert 58.0 g of glucose to CO 2 and H 2 O and Calculate the number of grams of CO2CO2 produced.

Answer 1

Solution Given C6H12O6 canst 602 (9) 6C02(q) + 6H₂0 (1) weight of glee cose C6H12O6 is 58.0 g molare mass of glucose = (12x6+ 1812+1686) 0/mal = 180g/mol hence number of moles of glucose = weight of C6H12O6 - malare mass of C6H12O6 = 58g - 180g/mol = 0.322 mol By stoichiometry I mole of C6H12O6 requires 6 moles of Oz = 0.322 mole of Co Hi2O6 requees = 0.322 x 6 moles =11932 moles of * 1.932 moles of 0 = weight of Oz weight of or requvied =° 1932 mol x 32 g/mol 32 g/mol 3 = 61.824 g - Again by stoichiometry 1 mol of C6H12Ood produces & moles of CO2 2 0.322 mole of C6H12Oo produce = 0.32226 = 1.932 mol of Co, I weight of CO₂ = 1.932 mol X 44 9 Imal = 185.0089]