Homework Answers
Hi Dear, my sincere apologies that this spectrum does not belongs to 2-methylpentane. Because 2-methylpentane is an aliphatic hydrocarbon without any strong electronegative atoms such as oxygen, fluorine, nitrogen. Only aldehydes & carboxylic acid protons will show a peak > 9 ppm chemical shift. I am already answered this in past, but i do not know whether that person is also you or someone!
The compound is heptanaldehyde and assignment has been shown below. This is 100% sure
HA proton of aldehyde involves in keto-enol tautomerism H2C-C(H)=O <==> HC=CH-OH, now enolic proton couples with adjacent HB and shows doublet splitting, same time HB shows triplet of doublet splitting.
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1. List and comment on the
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more information, but I was unsure what the individual needed. If
you need additional information, please be descriptive with what
you need! Thank you so much :)
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