Question

please include a free body diagram for explanation amd how to solve

2. A steel beam has a length of 8.0 meters and a mass of 175 kg. It is placed on a fulcrum 2.5 meters from the left edge. A concrete block of mass 120 kg is placed 3.5 meters to the right of the fulcrum. Clearly, the beam would rotate clockwise in this situation. To prevent the rotation, a vertical cable is connected to the right edge of the beam, as shown below a. What is the tension in the cable? b. What upward force is provided by the fulcrum? Vertical cable 8.0 m + 2.5 m 3.5 m

Answer 1

a sm - - Cable €2.5m k 3.5mm beam has mass 175kg. and longith smo Mass of block m=12ok FB.D of beam. x 3.5 Normal block - 22.5 k 1. se Grom simen that beam is ? rest so, net force on beam is equal to zero. we know that when a body is in equillibrium then it Jatisy two conditions 6 Net external force is zero z Fend to (11) Net external torsque is zero z Text to Beam may rotate about point if there is not any cable.

Net force on beam { Fent zo +T = my ang to centre of mass c. Net tosque about then, 2 Zent=0 >07 min = (s.5) T singo (R) หงาย 3) pang = (mg) 2 singu (8) = 2mg (-2) wow met => torque Text =0 5.67 -1.5W ~2 mg = 0

5.5T - 1.5N = 2400 (2) we com solve equations (1) and (2) theng multiply equation (1) by 1.5 them, 1.50+ 1.5T=4425 (3) - Adding Eq (2) and ley (3) 7T = 6825 T= 975 Newton So, tension in cable is 975 Newton, Now, force provided by the reasons fulcrum » putting name of T in equation (8) - 1:w+ (15) (975) = 4425 SN = 2962:5 AN I 1975 Newton fulcrum us 1975 Newtons. So, force provided by