Homework Answers
All these numbers are different then chances of having more than 2 PSNE are none.
Because to have 3 out of 4 values then we must have equality between these numbers atleast once which is not the case here
Let's see if a>e and c>g then we have one NE for sure
If a>e and c<g & b<d ,f>h then no Pure Straegy Nash EquiiliEqui
If a>e , c<g & b<d, f<h then one PSNE
If a>e, c<g & b>d, f<h then we have 2 PSNE
Hence it is possible to have no PSNE, 1 PSNE or 2 PSNE.
Option A is correct
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