Question

In yeast, ethanol is produced from glucose under anaerobic conditions. A cell‑free yeast extract is placed in a solution that contains glucose....

In yeast, ethanol is produced from glucose under anaerobic conditions. A cell-free yeast extract is placed in a solution that contains 3.00 x 10 mmol glucose, 0.40 mmol ADP, 040 mmol P. 0.80 mmol ATP, 0.20 mmol NAD*, and 0.20 mmol NADH. It is kept under anaerobic conditions. What is the maximum amount of ethanol (in millimoles) that could theoretically be produced under these conditions? maximum amount of ethanol: mmol Under the same conditions, what is the theoretical minimum amount of glucose (in millimoles) required in the solution to form the maximum amount of ethanol? minimum amount of glucose required: mmol

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Answer 1

Solution. Each glucose molecule is broken down into tomo pyruvate molecules in a process known as glycolysis. Cilycolysis is summerized by the equation: C6H12O6 +2 ADP +2 Pi + 2 NAD -> 2CH.Cocoo +2A1P+2NADH+2420727 Again thi's CHCOCOO reacts to form ethanol according to the Folloveing seachin - & CHỤo Cco > 80% CHO + 2cm. 2 CH ₂ CHO + QNADH 2 C₂H5OH Combining all, we get a C6H12O6 + 2 ADP +2 P; 2CH SOM + Q ATP + aca from the coefficients is the reactions, we obtain that 8x102 mmol glucose = 600 mmol ethanol. 45 0:40 ADP = 0.40 mmol ethanol 0.40 mmol Pi = 0.40 mmol etanol Hence, of all the seactants, ADP of Pi forms Yeast least amount of ethanol & hence they are the limiting reagent, Maximum amendef Ethanol =10.40 mmol/ fact. So, here 0.40 mmol of ethanol is being for med 1 mole of blucose gives a moles 'Ethanol. so for 0.40 mmol of ethanol We need half of that ie 0.20 mmol of glucose. Minimum amount of glucose required : 10-20 mmol. | mmol.