Question

Question 7 2 pts Molality An anti-freeze solution is prepared by dissolving 25.5 g of ethylene glycol (C2H602) in 769.0 g water to make 775 mL of solution? Input numbers only, with correct number of significant figures. Do not use scientific notation. a) What is the molarity of the solution? Methylene glycol b) What is the molality of the solution? methylene glycol c) What is the density of the solution? g/mL Il Proctorio is sharing your screen. Stop sharing Hide

Answer 1

Ethylene glycol CH₂-OH ең, он (C₂H2O) y given mass of ethylene glycol = 25.5g .. Molarmars of ethylene glycol = 2x12 + 6*1 + 2x16 = 24 76 +32 V Volume of solution = 775 me 262 g/mole x olarity is defined in the no. of moles of solute dissolved per litre - of solution. Note! M = Moto (no of moles of solute = given mas l Vs (me) Ethylene glycoll M COM, Oz X1000 - 25,5 x 100o 62 62 *995 x 775 - 0.581 m urs = 0,531 M or 01531 mola Molar mais Y perks of * molality is defined as the no. of mole, of solute dissolved solvent. Here water is the solvent, Itho = 769g = 0.769 Kg mo salute Isolvent (Kg)

mo 25, mere mo 2.2 80.ven mosle m-s molin 62 x 0.3 ma 0.535 molal or 0.535m solution is made up of solute (ethylene glycol) + water (solvent) grams of solution - Isolate + 9 water En 225.5+769=794254 volume of Solution = 775 ml to Density of solution = grams of solection Volume of solution 2 794.5 775 I g/ml = 1.03 g/me