Question

RESULTS Run two patients or control samples on the Medonie. Check the results to make sure that specimen with abnormal result
e. Hemoglobin = 18.0 g/dL RBC Count = 4.5 (x10/L) MCH= 1. Hemoglobin = 15 g/dL RBC Count = 3.8 (x10/L) MCH Calculate the MCHC
6. Calculate indices from the following results and state the expected RBC morphology (macroete, microcytic normocytic) and (
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Answer #1

1)

a) Hemoglobin : DIRECTLY measured.

b) Hematocrit : CALCULATED

​​​​​c) MCV : DIRECTLY measured.

d) MCH : CALCULATED

e) MCHC : CALCULATED

f) RDW : CALCULATED

2)

MCV = Hematocrit / RBC Concentration

a) Hematocrit = 24.5 % = 0.245

RBC concentration = 3.5 x 106 / uL

​​​​​​MCV = 0.245 / [(3.5 x 106)/10-6L] = 70 fL

b) Hematocrit = 45 % = 0.450

RBC concentration = 4.2 x 106/ uL

MCV = 0.450 / [(4.2x106)/10-6L] = 107.1 fL

c) Hematocrit = 32 % = 0.320

RBC concentration = 2.8 x 106 / uL

MCV = 0.320 / [(2.8x106)/10-6L] = 114.2 fL

MCH = ( Hemoglobin in g/dL x 10) / RBC concentration

​​​​​​d) Hemoglobin = 10.0 g/dL

RBC concentration = 3.2x106/uL

MCH = (10 x 10) / (3.2x106) = 31.25 picograms

e) Hemoglobin = 18.0 g/dL

RBC concentration = 4.5x106/uL

MCH = (18 x 10) / (4.5x106​​​​​​) = 40 picograms

f) Hemoglobin = 15.0 g/dL

RBC concentration = 3.8x106/uL

MCH = (15 x 10) / (3.8x106) = 39.47 picograms

MCHC = ( Hemoglobin in g/dL x 100) / Hematocrit in %

g) Hemoglobin = 11.0 g/dL

Hematocrit = 33%

MCHC = (11x100) / 33 = 33.33 g/dL

h) Hemoglobin = 6.0 g/dL

Hematocrit = 20%

MCHC = (6x100) / 20 = 30 g/dL

i) Hemoglobin = 15.0 g/dL

Hematocrit = 45%

MCHC = (15x100) / 45 = 33.33 g/dL

  

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