Ans:
Here I am considering NET magnification of two lens system.
Fe = 5 cm
Fo = 0.52 cm
Formulas :
Resolution = 1.22λ / (NA(obj) + NA(cond))
Numerical aperture (NA) = D/2f
1/di = 1/Fo – 1/do
Mnet = (Mobj)(Meye)
Mobj = -(di/do)
For 4X
do = 0.620 cm
Mobj = -0.666
d'i = -1.4398 cm
d'o = 0.239 cm
Meye = 6
Resolution = 2.75 µm
NA = 0.10
For 10X
do = 0.643 cm
Mobj = -1.606
d'i = -2.61 cm
d'o = 0.419 cm
Meye = 6.22
Resolution = 1.1 µm
NA = 0.25
For 40X
do = 6.2 cm
Mobj = -1.606
d'i = -14.398 cm
d'o = 2.39 cm
Meye = 6.22
Resolution = 0.42 µm
NA = 0.65
For 100X
do = 6.43 cm
Mobj = -1.606
d'i = -26.1 cm
d'o = 4.19 cm
Meye = 6.22
Resolution = 0.22 µm
NA = 1.25
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