Question

#1.(30pts, 15 pts each) (g) Consider a 135 meter high waterfall. If the decrease in potential energy of the water (i.e., mgh) is totally converted into heat, calculate the temperature difference between the top and bottom of the waterfall. Data: m = mass, g = acceleration due to gravity 9.81 m/s". The specific heat of water 4.184 J/(0°C). (h) If a system absorbs 30.0 J of heat from the surroundings, and if it also decreases its internal energy by 33 J, compute the work (w) associated with this process. Interpret the sign of your answer

Answer 1

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(g) Let mass of water = m. Potential Energy = mgh n=136 m. E = m (9:8) (136) f Q = heat Regiered in temperature nse Q = me AT = m (4.184 8/20) T nence, &= & .. тусдT = м а и AT= 9h/c = 9.8x135 °C 2 316°C 4.184 done © first law. of thermodynamics. &= outo so Penternal Energy w o work & neat added a 300 Q&AU = -331 wa d-AU = 30 +33 = 631 work done - 31