Question 6 Oxygen gas can be generated by heating KClO3 in the presence of a catalyst....
Use the References to access important values if needed for this question. Oxygen gas can be prepared by heating potassium chlorate according to the following equation: 2KCIO3(s)— 2KCI(s) + 302(g) The product gas, 02, is collected over water at a temperature of 25 °C and a pressure of 747 mm Hg. If the wet O2 gas formed occupies a volume of 6.24 L, the number of grams of O2 formed is g. The vapor pressure of water is 23.8 mm...
Oxygen gas can be prepared in the laboratory by heating potassium chlorate, so that it decomposes according to the equation: What would the pressure of O2 be in a 2.50 L glass container at 220°C if 6.50 g of KCIO3 is decomposed? Multiple Choice 0.0796 atm 178 atm 662 atm < Prev 6 of 16 Nht >
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s) . The equation for the reaction is 2KClO3⟶2KCl+3O2 Calculate how many grams of O2(g) can be produced from heating 70.4 g KClO3(s) STRATEGY: Convert the mass of KClO3 to moles. Convert the number of moles of KClO3 to the number of moles of O2 . Convert the number of moles of O2 to grams. Step 1: 70.4 g KClO3 is equal to 0.574 mol KClO3...
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s). The equation for the reaction is 2KClO3⟶2KCl+3O2 Calculate how many grams of O2(g) can be produced from heating 98.6 g KClO3(s). mass:
Magnesium oxide can be made by heating magnesium metal in the presence of the oxygen. The balanced equation for the reaction is 2 Mg(s)+O2(g) 2 MgO(s) Consider that you react 12.62 g Mg with 13.08 g O2 gas. What is the theoretical yield of MgO that can be generated from this reaction? Enter a numerical answer only to three significant figures, in terms of grams.
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s). The equation for the reaction is 2KClO3⟶2KCl+3O2⟶2KCl+3O2 Calculate how many grams of O2(g) can be produced from heating 48.8 g KClO3(s).
Question 4 1 pts Given the decomposition reaction of KClO3(s), 2 KCIO3(s) 2 KCl(s) + 3 O2(8) If 19.6 L of oxygen gas (O2) are produced at 198 °C and 760 torr, answer all three parts below. 1) The number of moles of O2(g) produced → [Select ] 1.21 mol 385 mol 2) The number of moles of KCIO3(s) require 0.507 mol 917 mol problem is Select] 2(g) as stated in the 2) The grams of KCIO3(s) required to produced...
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Question 2 1 pts Given the following unbalanced reaction: KCIO3 ---> KCI + O2 How many moles of Oz can be produced by letting 45.7 g of KCIO3 react? - Question 3 1 pts Given the following unbalanced reaction: Na2O + H2O ---> NaOH How many grams of NaOH is produced from 2.78 x 10 grams of Na O?
Use the References to access important values if needed for this question. Oxygen gas can be prepared by heating potassium chlorate according to the following equation: 2KCIO3(s)—>2KCl(s) + 302(g) The product gas, O2, is collected over water at a temperature of 25 °C and a pressure of 749 mm Hg. If the wet O2 gas formed occupies a volume of 8.32 L, the number of grams of O2 formed is g. The vapor pressure of water is 23.8 mm Hg...
You are given an unknown containing KClO3. Following the procedure in your manual, you obtain the following fictional data Note! For this problem use the given (allbeit incorrect) vapor pressure of water Mass of empty test tube 71.8394 g Mass of test tube + unknown 72.1363 g Mass of test tube + unknown + MnO2 72.3077 g Mass of erlenmeyer flask with residual water 323.06 g Mass of erlenmeyer flask filled with water 358.52 g Atmospheric pressure 760.9 mmHg Temperature...