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b) A contracted invests $50,000 at an interest rate of 5% three years from now and continues to make annual deposits increasi

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Answer #1

Amount in the account at the end of 15 years from now=50000/1.05^3*(1-(1.06/1.05)^13)/(1-(1.06/1.05))*1.05^15
=$12,36,395.59

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